If cos A+iB) = cos & sino show that
Cos 2A+Cos h
B=2
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sin2A+sin4A=1−cos2A+(1−cos2A)2
sin2A+sin4A=1−cos2A+(1−cos2A)2=cosA+cos2A, as given cosA+cos2A=1
sin2A+sin4A=1−cos2A+(1−cos2A)2=cosA+cos2A, as given cosA+cos2A=1=1
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