Question

if cos A is equal to under root 3 upon 2 find the value of one by tan A + sin a upon 1 + Cos A​

Answer 1

Answer:

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Answer 2

Answer:

The value of the given expression is $\frac{tanA+sinA}{1+cosA}=\frac{1}{\sqrt{3} }$

Step-by-step explanation:

Given that,

The value of cosine function is $CosA=\frac{\sqrt{3} }{2}$

Then the value of angle is $A=cos^{-1}(\frac{\sqrt{3} }{2} )=30^{0}$

And the expression which we are required to find is

$\frac{tanA+sinA}{1+cosA}$

substituting the value of angle in the above expression,we get

$\frac{tan30+sin30}{1+cos30} =\frac{\frac{1}{\sqrt{3} }+\frac{1}{2} }{1+\frac{\sqrt{3} }{2} } \\=\frac{2+\sqrt{3} }{2+\sqrt{3} } \times \frac{1}{\sqrt{3} } =\frac{1}{\sqrt{3} }$

Therefore,the value of the given expression is $\frac{tanA+sinA}{1+cosA}=\frac{1}{\sqrt{3} }$

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