Question

if Cos A minus b equals to root 3 by 2 and Sin A + B equal to 1 then find the value of a and b​

Answer 1

$\cos(a - b) = \frac{ \sqrt{3} }{2}$
but
$\cos(30) = \frac{ \sqrt{3} }{2}$
Hence
$a - b = 30$



Now
$\sin(a + b) = 1 \\ \\ but \\ \\ \sin(90) = 1 \\ \\ hence \\ \\ a + b = 90$
By solving them simultaneously
we get

$a = 60 \\ b = 30$

Answer 2

Answer:

a=30

b=60

Step-by-step explanation:

Hii,

You will get the answers in the attachment.

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