Question

if Cos A minus b is equal to 3 by 5 and 10 into 10 b is equal to 2 then

Answer 1

Cos(a-b) = cosACosB+sinAsinB
Given tanAtanB=2
SinAsinB/cosAcosB=2
SinAsinB=2cosAcosB
Put the value of sinAsinB
CosACosB+2cosAcosB=3/5
3cosAcosB=3/5
CosAcosB=1/5

Answer 2

Answer:

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