Question

if cos A = root 3 then sin A is

Answer 1

cosA=$\sqrt{3}$=base/hypotenuse

so base=$\sqrt{3}$

and hypotenuse=1

now by pythagors theorm

(hypotenuse)^2=(base)^2+(height)^2

1=3+(height)^2

3+(height)^2=1

(height)^2=-2

height=$\sqrt{-2}$

sinA=$\sqrt{-2}$/1

Answer 2

Answer:

Step-by-step explanation: