if cos A - sin A= 1, then prove that cos A+ sinA=1 or -1
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cosθ+sinθ=1
(cosθ+sinθ) ^2 =1^2
cos 2θ+sin 2θ+2sinθcosθ=1
1+2sinθcosθ=1
2sinθcosθ=0
sinθcosθ=0
Now (cosθ−sinθ) 2
=(cosθ+sinθ) 2−4sinθcosθ
=1 ^2 −4×0
=1
(cosθ−sinθ) 2
=1
cosθ−sinθ=±1
∴ Hence proved.
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