if cos A+sinA=√2cosA, show that cos A-sinA=√2sinA.
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Explanation:
cos A + Sin A =√2 cos A
(cos A +Sin A)²= (√2cos A)²
cos²A +sin²A +2 cos A sin A = 2 cos²A
sin²A+ 2 cos A sin A= cos²A
2 cos A sin A= cos²A - sin²A
2 cos A sin A=(cos A+ sin A)(cos A- sin A)
2 cos A sin A= √2 cos A (cos A- sin A)
therefore,on dividing both sides with √2 cos A
cos A- sin A= √2 sin A
H/P
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