If cos(a) = x/y find tan(a)
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cos(a) = x/y
In the triangle (right angled), cos(a) = adjacent side/hypotenuse = x/y
Let the other side be 'c'
y^2 = x^2 + c^2
c^2 = y^2 - x^2
c = root(y^2-x^2) = opposite side
Tan(a) = opposite side/adjacent side = root(y^2-x^2)/x OR root[(x+y)*(y-x)]/x
Hope it helps.
In the triangle (right angled), cos(a) = adjacent side/hypotenuse = x/y
Let the other side be 'c'
y^2 = x^2 + c^2
c^2 = y^2 - x^2
c = root(y^2-x^2) = opposite side
Tan(a) = opposite side/adjacent side = root(y^2-x^2)/x OR root[(x+y)*(y-x)]/x
Hope it helps.
aadilmohammad:
Thanks same answer
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