Question

If cos alpha = 1/2 and tan beta =1/√3 then find sin (alpha +beta)

Answer 1

Answer:

1

Step-by-step explanation:

Let alpha be a and beta be b, so the question becomes:

If cos a = 1/2 and tan b =1/√3 then find sin (a + b)

Cos 60 = 1/2 and tan 30 = 1/√3

So, Cos 60 = Cos a and tan 30 = tan b

On comparing, a = 60 and b =30

So Sin (a + b) = Sin 90 = 1

Answer 2

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Answer:

1

Step-by-step explanation:

cosα = $\frac{1}{2}$

cos60 = $\frac{1}{2}$

∴ α = 60°

tanβ = $\frac{1}{\sqrt{3} }$

tan30 = $\frac{1}{\sqrt{3} }$

∴ β = 30°

sin(α + β)

⇒ sin(60 + 30)

⇒ sin90 = 1