If cos alpha/cos beta=m and cos alpha/sin beta=n, show that (m2 +n2) cos2alpha=n2
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Cos a /cosb=m, cos a /sin b=n
LHS
[(cos a/cosb) ^2 + ( cos a/sin b)]+ cos^2b
[cos^2a/cos^2b+cos^2a/sin^2b]+ cos^2b
[cos^2a(sin^2b+cos^2b)/sin^2b]
Cos^2a(1)/sin^2b
n^2
Hope it helps but check the question its wrong
LHS
[(cos a/cosb) ^2 + ( cos a/sin b)]+ cos^2b
[cos^2a/cos^2b+cos^2a/sin^2b]+ cos^2b
[cos^2a(sin^2b+cos^2b)/sin^2b]
Cos^2a(1)/sin^2b
n^2
Hope it helps but check the question its wrong
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