Question

If cos alpha + sec alpha = 2, then cos^8 alpha + sec^8 alpha = ....​

Answer 1

Answer:

let us assume theta symbol $

given,

cos$+sec$=2,

cos$+1/cos$=2,

cos^$+1=2cos$,

cos^$=2cos$-1

now,

cos^8+sin^8

=> 2cos8–1+1-cos^8

=> 2cos8–1+1–(2cos8–1) [since,cos^$=2cos$-1]

=> 2cos8–1+1–2cos^8+1

=> 1

THEREFORE,cos^8+sin^8=1

Step-by-step explanation:

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Answer 2

Answer:

256

Step-by-step explanation:

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