if cos B= 1/3 find the other trignometric ratio
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cosx=1/3
u can do this in two ways
M1:
just draw a triangle and solve it
M2:
use the trigonometric equations
i will do it with the 2nd one
sinx=√(1-cos²x)
=√(1-1/9)
=2√2/3
tanx=sinx/cosx
=2√2/3/1/3
=2√2
others are just reverse of the given three
secx=3
cosecx=3/2√2
cotx=1/2√2
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