Question

If cos B=1/3 then find tan B and cosec A
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Answer 1

Answer:-

Cos B = 1/3 = B/H

B = 1 and H = 3.

By Pythagoras theroem,

( H )² = (B)² + (P)²

( 3)² = (1)² + (P)²

( P )² = 9 - 1

P² = 8

P = √8 = √2 × 2 × 2

P = 2√2.

Therefore,

Tan B = P/B = 2√2/1 = 2√2

Cosec B = H/P = 3/2√2

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