Question

if cosα/cosβ = m, cosα/sinβ = n, show that (m²+n²)cos²β = n²

Answer 1

Answer:

the solution is given in following discription,

i hope that u can understand this solution

Step-by-step explanation:

given that

cos a= m

cos b

cross multiply

we get

→ cos a = (cos b)m —1

and another condition is

cos a = n

sin b

again cross multiply we get

→cos a = (sin b)n —2

equate both 1 and 2 we get

→(cos b )m = ( sin b)n

by squaring on both sides

we get

→(cos² b)m² = ( sin ²a)n²

using sin²a = 1-cos²a

we get

→(cos²b)m² = (1 - cos²b)n²

→(cos²b)m² = n² - (cos ²b)n²

→(cos²b)(m²+n²)=n²

Answer 2

Here is your answer

I know my writing is so bad