If cos e +sin” =m, then
a) 1<m < 2
b) 1/2<m<1
c) 3/4<m <1
d) 3/4<m<13/16
Answers
Answered by
0
Answer:
Please mark me at brainlist ....
Step-by-step explanation:
A=sin
2
θ+cos
4
θ
=sin
2
θ+cos
2
θ.cos
2
θ
=sin
2
θ+cos
2
θ(1−sin
2
θ)
=sin
2
θ+cos
2
θ−sin
2
θcos
2
θ
=1−
4
1
(2sinθcosθ)
2
=1−
4
1
sin
2
2θ
Min.(sin
2
2θ)=0
Max.(sin
2
2θ)=1
Min.(A)=1−
4
1
.Max(sin
2
2θ)
=1−
4
1
.1=
4
3
Max.(A)=1−
4
1
.Min.(sin
2
2θ)
=1−
4
1
.0=1
∴
4
3
≤A≤1
Hence, option 'B' is correct.
Attachments:
Similar questions