Math, asked by asmit1655, 9 months ago

If Cos o + sin o = √2
Prove that Cos 0 - sino = √2 sin o ​

Answers

Answered by mominkafil1122
4

Answer:

Step-by-step explanation:

i will be using A instead of o

we have ,

cosA - sinA=√2 sinA

squaring both the sides

=>(cosA - sinA)²=2 sin²A

=>cos²A+sin²A-2sinAcosA=2sin²A

=>sin²A-2sin²A-2sinAcosA= -cos²A

=> -sin²A-2sinAcosA= -cos²A

=> sin²A+2sinAcosA=cos²A

adding cos²A on both the sides

=> cos²A+sin²A+2sinAcosA=2cos²A

=> (cosA+sinA)²=2cos²A

=> cosA+sinA=√2cosA

Answered by alexvsakha
3

Answer:

Step-by-step explanation:

cos0 + sin0 = \sqrt{2}                         (given)

(cos0 + sin0)^{2}= 2                          (squaring both sides)

cos^{2}0  + sin^{2}0 + 2cos0.sin0 = 2   ( cos^{2}0  + sin^{2}0 = 1)

1 + 2cos0.sin0 = 2

2cos0.sin0=2 - 1

cos0.sin0 = 1÷2      

sin0 = 1/2cos0-------------{1}

                       

Else, you can solve.

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