Math, asked by Sopenyter1842, 1 year ago

If cos pi/7, cos 3pi/7, cos 5pi/7 are the roots of the equation ax^3+bx^2+cx+d=0, then

Answers

Answered by maheshv22
0

sum \: of \: the \: roots =  - coeff \:o of {x}^{2}  \div coeff \: of \:  {x}^{3}  =  - b \div a \\  \cos(\pi \div 7)  +  \cos(3\pi \div 7)  +  \cos(5\pi \div 7)  =  - b \div a \\

prpdu

product \: of \: roots =  - d \div a =  \cos(\pi \div 7)  \cos(3\pi \div 7)  \cos(5\pi \div 7)  =  - d \div a

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