Question

If cos q =2/3 then find 2 sec2q +2tan2q-7

Answer 1

Answer: cos q=2/3

cos a= b/p

h^2-b^2=p^2

9-4=√5

sec 2q=2×3/2=3

tan 2q =p/b

√5/2×2=√5

now 2 sec2q+2tan2q-7

2×3+√5×2-7=2√5-1

Explanation:hope it help you