If cosθ + secθ = 2, then find the value of cos²θ+sec²θ.
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Answer:
zero
Step-by-step explanation:
by using the algebraic identity a²+b²= (a-b)²-2ab you will get ( cos theta + sec theta) - 2costhetha sectheta.....
substitute the value of cos thete + sec theta for 2 then write sec theta in the form of 1/cos theta...then solve to get zero...
hope this helps you matey!!!!
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