Question

If ( cos θ + sec θ) = 5/2 then ( cos^2 θ + sec^2 θ) = ? (a) 21/4 (b) 17/4 (c) 29/4 (d) 33/4

Answer 1

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Answer 2

Answer:

Option   (b) 17/4

Step-by-step explanation:

Suppose A = Cos θ

And          B = Sec θ

we know (A + B)²= A² + B²+ 2 A B

Then We can Find Value In A² + B²

like this type  (A + B)² - 2 A B = A² + B²......................Equation (1)

now then put A, B Value in Equation (1)

We Can Write

( Cos θ + Sec θ)² - 2 Cos Θ . Sec Θ = Cos² Θ Sec² Θ

( 5/2 )²- 2 = Cos² Θ + Sec² Θ

25/4 - 2 = Cos² Θ + Sec² Θ

(25-8)/4 = Cos² Θ + Sec² Θ

17/4 = Cos² Θ + Sec² Θ