Question

if cos(sin^-1 2/5+cos^-x)=0.then x is equals to​

Answer 1

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Step-by-step explanation:

ANSWER ::

cos(sin^-1 2/5+cos^-1 x) = 0

⟹ sin^-1 2/5+cos^-1 x = cos^-1 0

⟹ sin^-1 2/5+cos^-1 x = 90°

⟹ sin^-1 2/5 = 90° - cos-1 x

⟹ sin^-1 2/5 = sin^-1 x

⟹ x = 2/5