Question

if cos θ:sin θ=1:2 then find the value of 4 sinA- 3cos A÷ 2 sin A+ 3 cos A​

Answer 1

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Answer 2

Answer:

$\frac{ \cos \theta }{ \sin \theta } = \frac{1}{2} =⟩ \cot \theta = \frac{1}{2} \\ \\ \frac{4 \sin \theta - 3 \cos \theta}{2 \sin \theta + 3 \cos \theta} \\ \color{blue} \underline{dividing \: denominator \: by \: \sin \theta } : \\ = \frac{ \frac{4sin \theta}{ \sin \theta } - \frac{3 \cos \theta }{ \sin \theta} }{ \frac{2 \sin \theta}{ \sin \theta} + \frac{ 3 \cos \theta}{ \sin \theta} } \\ \\ = \frac{4 - 3 \cot \theta}{2 + 3 \cot \theta} \\ \\ = \frac{4 - 3 \times \frac{1}{2} }{2 + 3 \times \frac{1}{2} } \\ \\ = \frac{8 - 3}{4 + 3} \\ \\ = \frac{5}{7} \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$