If cosΦ +sinΦ=√2cosΦ show that cosΦ-sinΦ=√2
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hey mate :-
look this attachment :-
hope it helps you dear!!!
thanks
look this attachment :-
hope it helps you dear!!!
thanks
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HridayAg0102:
U must hv pointed out the mistake to the questioner
Answered by
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(cosA+sinA)=√2cosA
Now squaring both side
(cosA+sinA)^2=(√2cosA)^2
cos^2A+sin^2A+2sinA.cosA=2cos^2A
cos^2A-sin^2A=2sinA.cosA
(cosA-sinA)^2=cos^2A+sin^2A-2sinA.cosA
(cosA-sinA)^2=cos^2A+sin^2A-cos^2A+sin^2A
(cosA-sinA)^2=2sin^2A
cosA-sinA=√2sinA
Now squaring both side
(cosA+sinA)^2=(√2cosA)^2
cos^2A+sin^2A+2sinA.cosA=2cos^2A
cos^2A-sin^2A=2sinA.cosA
(cosA-sinA)^2=cos^2A+sin^2A-2sinA.cosA
(cosA-sinA)^2=cos^2A+sin^2A-cos^2A+sin^2A
(cosA-sinA)^2=2sin^2A
cosA-sinA=√2sinA
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