Question

If (cosθ–sinθ)/(cosθ+sinθ) = (1–√3)/(1+√3), then find the value of θ.

Answer 1

Answer:

(cosθ–sinθ)/(cosθ+sinθ) = (1–√3)/(1+√3)

Divide LHS by cos theta- we'll get:

(1-tan theta)/(1+tan theta)= 1-root3/1+root3(rationalize the RHS)

 (1-tan theta)/(1+tan theta)=root3-2

so, 1-tna theta= root3-2 + (root3-2)tan theta

take tan theta terma to one side you'll get:

tan thete(root3-1)=3-root3     (take root 3 common from RHS)

tan theta=root3

tan theta=tan 60

theta=60 degree.

ok..... thankss