If cos+sin= root over 2 * cos, show that cos−sin=root over 2 *sin.
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Heya User ,
--> cos θ + sin θ = √2 cos θ
--> sin θ = √2 cos θ - cos θ
=> sin θ = ( √2 - 1 ) cos θ
=> [ sin θ / ( √2 - 1 ) ] = cos θ
=> [ sin θ ( √2 + 1 ) / ( 2 - 1 ) ] = cos θ
0_0 --> We rationalized the denominator in the 2nd step ^_^
=> [ √2 sin θ + sin θ ] = cos θ
=> cos θ - sin θ = √2 sin θ
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