Math, asked by InnocentBOy143, 1 year ago

If cos∅= $\frac{1}{\sqrt{122} }$ , then find tan∅.

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Answered by Anonymous

SOLUTION

$cos \theta = \frac{Base }{Hypotenuse} = \frac{1}{ \sqrt{122} } \\ \\ = > {P}^{2} = {H}^{2} - {B}^{2} \\ \\ = > {P}^{2} = ( { \sqrt{122} )}^{2} - ( {1)}^{2} \\ \\ = > {P}^{2} = 122 - 1 \\ \\ = > {P}^{2} = 121 \\ \\ = > P = \sqrt{121} \\ \\ = > P = 11cm \\ \\ now \\ = > tan \theta = \frac{P}{B} = \frac{11}{1} = 11cm$

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Answered by rishabh1894041

Step-by-step explanation:

$cos \alpha = \frac{1}{ \sqrt{122} } \\ {cos}^{2} \alpha = \frac{1}{122} \\ 1 - {sin}^{2} \alpha = \frac{1}{122} \\ {sin}^{2} \alpha = \frac{121}{122} \\ sin \alpha = \frac{11}{ \sqrt{122} } \:, \: \frac{ - 11}{ \sqrt{122} } \\ \\ tan \alpha = 11 \: , \: - 11 \\ If cosA is in first quadrant, then tanA is in first quadrant, hence positive & if cosA is in fourth quadrant, tanA is in fourth quadrant, hence tanA is negative value.\\ hope \: it \: willhelp \: you..$

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If cos∅=, then find tan∅.

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If cos∅= $\frac{1}{\sqrt{122} }$ , then find tan∅.