Question

If cos theeta +sin theeta=underroot2 cos theeta,show that cos theeta -sin theeta=underroot 2 sin theeta

Answer 1

heya☺

it's too easy .

cos¢+sin¢=√2(given)--------1)

(cos¢-sin¢)^2+(cos¢+sin¢)^2 【adding cos¢-sin¢)^2

cos^2¢+sin^2¢-2sin¢.cos¢+cos^2¢+sin^2¢+2cos¢●sin¢

(cos¢+sin¢)^2+(cos¢-sin¢)^2=2

now,from 1)putting cos¢+sin¢=√2

so,we get. ,,cos¢-sin¢=0


hope it help you.

@rajukumar .☺☺

Answer 2

Answer:

here is ur required answer

Step-by-step explanation:

Sin θ+cos θ=√2

Now we have to Square on both sides

={sin θ+cos θ}²=√2²

={sin² θ+cos ² θ}+2 sin

θ cos  θ=2

=1+sin θ cos θ=2

⇒sin θ cos θ=1/2

Now,

Tan θ+cot θ=sin θ/cos θ+cos θ/sin θ

={sin² θ+cos² θ} /sin θ cos θ

=1/ {1/2} = 2

Hence,the answer is "2".