If cos theta = 1/2 ( a + 1/ a ) prove that 2 cos 4 theta= a4 +1/a4
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Answered by
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Step-by-step explanation:
A^6+a^4+a^2+1=a^4(a^2+1)+1 (a^2+1)
= (a^2+1)(a^4+1).... (eq 1)
here,
a=(1+i)/root 2
or root2*a=1+i
squatting both sides
2a^2=(1+i)^2
or 2a^2=1+2i+i^2
or 2a^2=1+2i+(-1) since i^2=(-1)
a^2=i
or a^4=i^2=(-1)
so from eq (1) ....
a^6+a^4+a^2+1 =(a^2+1)(a^4+1)= (i+1)(-1+1)= 0*(i+1)=0
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Step-by-step explanation:
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