if cos theta 1=2 cos theta 2 then find the value of tan theta1- theta2/2tan theta1+theta2/2
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cosθ1=2cosθ2
cosθ2cosθ1=2
Applying componendo and dividendo, we get
cosθ1−cosθ2cosθ1+cosθ2=2−12+1
⇒−2sin(2θ1+θ2)sin(2θ1−θ2)2cos(2θ1+θ2)cos(2θ1−θ2)=3
⇒tan(2θ1+θ2
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