If cos theta =1/2 find the sin theta and tan theta
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Answered by
11
hey bestie here is your answer
cos theta =1/2 =60° sin 60° = √3/2
tan theta = sin /cos = √3/2 ×2 =√3
hope it helps
cos theta =1/2 =60° sin 60° = √3/2
tan theta = sin /cos = √3/2 ×2 =√3
hope it helps
Answered by
3
Hey"
Here is your answer.
☆ Cos@=b/h=1/2 (given)
By pythagoras theorem
h2=P2+B2
(2)2=P2+(1)2
4=P2+1
3=p2
underoot3=p
☆ sin@=p/h=underoot3/2
☆tan@=p/b=underoot3/1
=underoot3
hope it is helpful to you.
Here is your answer.
☆ Cos@=b/h=1/2 (given)
By pythagoras theorem
h2=P2+B2
(2)2=P2+(1)2
4=P2+1
3=p2
underoot3=p
☆ sin@=p/h=underoot3/2
☆tan@=p/b=underoot3/1
=underoot3
hope it is helpful to you.
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