If cos theta = 1/√2 , then find the value of cos ^2 theta - don ^2 theta
Answers
Answered by
2
Hey mate hope it helps you...
cos ∆ = 1/√2
∆ = 45°
cos²∆ - tan²∆
= 1/2 - 1
= -1/2
Answered by
0
Answer:
Cos theta = 1 /√2
Cos Theta = Cos 45°
Theta = 45°
Cos^2theta - tan^2theta
=Cos^2 45° - tan^2 45°
= (1/√2)^2 - 1^2
= 1/2 - 1
=-1/2.
hope it helps..
Similar questions