if cos theta = 1/2(x+1/x), then 1/2(x²+1/x²)
sin 2 theta
cos 2 theta
tan 2 theta
sec 2 theta
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[tex]\mathrm{2\ ...f(x) = 2x1 + x2 now, f(tanθ) = 2tanθ1 + tan2θ = 2tanθsec2θ f(tanθ) = 2 sinθcosθ × cos2 θ = 2sinθcosθ f(tanθ) = sin 2θ
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