Question

if cos theta =1/3,then find the value of sin theta​

Answer 1

Answer:

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Answer 2

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Cos thetha = 1/3

Sin thetha = ?

Since cos thetha = B / H = 1 / 3

Using pythagoras theorem :-

H^2 = P^2 + B^2

3^2 = P^2 + 1^2

9 - 1 = B^2

B^2 = 8

B = 2_/2

Sin thetha = P / H = 2_/2 / 3