Question

if cos theta =1/3r then find value of cosec theta

Answer 1

Answer:

please please fallow me

Answer 2

Answer:

$cosec \: \theta = \frac{3}{2 \sqrt{2} }$

Step-by-step explanation:

if cos theta =1/3r then find value of cosec theta

we know that

$cos \: \theta = \frac{base}{hypotenuse} = \frac{1}{3}$

in a Right triangle if Base= k

Hypotenuse = 3k

then perpendicular=

$= \sqrt{9 {k}^{2} - {k}^{2} } \\ \\ = \sqrt{8 {k}^{2} } \\ \\ = 2k \sqrt{2}$

Now we know that

$cosec \: \theta = \frac{hypotenuse}{perpendicular} \\ \\ = \frac{3k}{2k \sqrt{2} } \\ \\ cosec \: \theta = \frac{3}{2 \sqrt{2} }$

Hope it helps you.