if cos theta= 1/root 3 then sec 2theta
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Answer:
1✓3 base = 1 hypotenuse= √3
√3²= 1² + Perpendicular ²
3 = 1 + perpendicular ²
3-1= 2 = perpendicular ²
perpendicular= √2
Sec = √2/√3
2× √2/√3
²√2/√3
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