If cos theta =1/root3. then find sin theta and tan theta .
(using formula sin^2 theta + cos^2 theta = 1) and for tan use tan theta = sin theta / cos theta
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Answered by
32
sin²a+ cos ²a=1
sin²a+(1/√3)²=1
sin²a= 1-1/3=2/3=√2/√3
since tan a=sin a/ cos a
√2/√3÷1/√3
√2/√3×√3/1
=√2
plzz mark me as brain list
sin²a+(1/√3)²=1
sin²a= 1-1/3=2/3=√2/√3
since tan a=sin a/ cos a
√2/√3÷1/√3
√2/√3×√3/1
=√2
plzz mark me as brain list
neh111:
I confused in the 3 step
1-1/3 1-1= 0 na
costeta =adj/opp
ask. means
adjacent side means base of triangle
Answered by
34
Given cos theta = 1/root3.
We know that sin^2 theta + cos^2 theta = 1
sin^2 theta + (1/root3)^2 = 1
sin^2 theta + (1/3) = 1
sin^2 theta = 1 - 1/3
sin^2 theta = 2/3
sin theta = root 2/root 3.
We know that tan theta = sin theta/cos theta
= root 2/root 3/1/root 3
= root 2.
Hope this helps!
We know that sin^2 theta + cos^2 theta = 1
sin^2 theta + (1/root3)^2 = 1
sin^2 theta + (1/3) = 1
sin^2 theta = 1 - 1/3
sin^2 theta = 2/3
sin theta = root 2/root 3.
We know that tan theta = sin theta/cos theta
= root 2/root 3/1/root 3
= root 2.
Hope this helps!
sin theta=root2/root3 tan theta= root2
in rt triangle hyp2=perp2+base2 : perp= root 2 : sin theta=perp/hyp =root2/root3 ; tan theta =prp/base = root2
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