Question

If cos theta = 1/(sqrt(7)) prove that (cos e * c ^ 2 * theta - sec^2 theta)/(cos e * c ^ 2 * theta + sec^2 theta) = - 3/4​

Answer 1

Answer:

tanθ=

7

1

⇒cotθ=

7

∴sec

2

θ=(1+tan

2

θ)=1+

7

1

=

7

8

and cosec

2

θ=(1+cot

2

θ)=1+7=8.

∴

cosec

2

θ+sec

2

θ

cosec

2

θ−sec

2

θ

=

8+

7

8−

7

8 =

64

48

=

4

3

.

Step-by-step explanation:

please mark me as brainliest