If cos theta = -12/13 & theta lies in 2 quadrant then find tan theta.
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Hypotenuse2 = 52+122
Hypotenuse=13
tanθ=12−5
cosθ=13−12 (θ lies in second quadrant)
sinθ=135
1−sinθ2cosθ=1−1352×13−12=13813−24=−3
Step-by-step explanation:
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Answered by
0
Answer:
Hypotenuse
2
= 5
2
+12
2
Hypotenuse=13
tanθ=
12
−5
cosθ=
13
−12
(θ lies in second quadrant)
sinθ=
13
5
1−sinθ
2cosθ
=
1−
13
5
2×
13
−12
=
13
8
13
−24
=−3
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