Question

If cos theta = 12/13 find the value of sin 0 and tan O
Also, find the value of 2 sin 0 - 4 tan 0, where
O is acute​

Answer 1

Step-by-step explanation:

$\sin( \alpha ) = \sqrt{ 1 - { \cos( \alpha ) }^{2} } = \sqrt{1 - { (\frac{12}{13}) }^{2} } = \frac{1}{13 } \\ \tan( \alpha ) = \frac{1}{12} \\ \\ 2 \sin( \alpha ) - 4 \tan( \alpha ) = \frac{2}{13} - \frac{4}{12} = \frac{6 - 13}{39} \\ \: \: \: = \frac{ - 7}{49}$

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