Question

If cos theta =15 upon 17 then find sin theta

Answer 1

Answer:

cos theta =15/17

Base=15 and hypotenuse=17

By Pythagoras theorem

(AC)²=(AB)²+(BC)²

(17)²=(15)²+(BC)²

289=225+(BC)²

BC=8

SIN theta =P/H

8/17

Answer 2

$\huge\sf\pink{Answer}$

☞ Your Answer is (8/17)

$\rule{110}1$

$\huge\sf\blue{Given}$

✭ $\sf cos \theta = \dfrac{15}{17}$

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

◈ The Value of $\sf sin \theta$

$\rule{110}1$

$\huge\sf\purple{Steps}$

We know that,

➝ $\sf cos \theta = \dfrac{15}{17} = \dfrac{Base}{Hypothenuse}$

$\bullet\:\underline{\sf By \ Pythagoras \ Theorem}$

➝ $\sf Perpendicular = \sqrt{Hypotenuse^2 - Base^2}$

➝ $\sf P = \sqrt{17^2-15^2}$

➝ $\sf P = \sqrt{64}$

➝ $\sf \orange{P = 8}$

So now the value of $\sf sin \theta$ is,

➢ $\sf sin \theta = \dfrac{Perpendicular}{Hypothenuse}$

➢ $\sf\red{ sin \theta = \dfrac{8}{17}}$

$\rule{170}3$