Question

if cos theta =2/3,find the value of 2 sec²theta +2tan²-9​

Answer 1

Answer:

Let ABC be a right angle triangle , right angled at B and C= theta

Therefore cos theta = 2/3 ( given)

And cos theta = BC/AC

So, BC=2 , AC = 3

So using Pythagoras theorem.

AB = √5

Now 2 sec squared theta + 2 tan squared theta -7=

2*9/4+2*5/4-7= 14/2-7= 7-7=0

Step-by-step explanation:

pls mark as brainiest