if cos theta=(2)/(3) then find 2 sec^(2)theta
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Given,
cosΦ = 2/3.
b/h = 2/3.
=> b = 2.
=> h = 3.
By using Pythagoras theorem, we get,
AB = √AC² - BC².
AB = √(3)² - (2)².
AB = √9 - 4.
AB = √5.
secΦ = h/b = 3/2.
Now,
2sec²Φ = 2(3/2)² = 2(9/4 = 18/4 = 9/2.
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