Question

if cos theta =2x/1+x^2. then tan theta = ?

Answer 1

Answer:

Given cos A = 2x / 1+x^2 = adjacent /hypotenuse

tan A = opposite / hypotenuse

opposite side =

$\sqrt({1 + {x }^{2} } {)}^{2} - 4 {x}^{2}$

by solving we get x^2 -1

tan A = x^2-1 / 1+ x^2

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Answer 2

Answer:

answer is 1-×^2/2x

Step-by-step explanation:

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