Question

if cos theta = 3\5, evaluate sin theta - cos theta/2 tan theta​

Answer 1

Answer:

cos © =3/5=b/h ,let b= 3k and h=5k ,

therefore p = 4k by Pythagoras theorem p=√h^2-b^2

(sin © - cos © )/2 tan ©

(4/5 - 3/5 )/2 X 4/3

(1/3)/8/3

(1 X 3)/(8 X3)

1/8 answer

Answer 2

cos theta =3/5

b=3

h=5

then p=4

sin theta=4/5

tan theta=4/3

(4/5-3/5)÷2×4/3

=1/5×3/8

=3/40 (ans)