Question

If cos theta 3 /5 then find sec theta.Sin theta .Tan theta

Answer 1

Step-by-step explanation:

$\sec( \alpha ) = \frac{1}{ \cos( \alpha ) } = \frac{1}{ \frac{3}{5} } = \frac{5}{3} \\ { \sin }^{2} \alpha = 1 - { \cos}^{2} \alpha = 1 - ( { \frac{3}{5} })^{2} \\ = \frac{25 - 9}{25} = \frac{16}{25} \\ hence \: \\ sin \: \alpha = \frac{4}{5} \\ \tan( \alpha) = \frac{ \sin( \alpha ) }{ \cos( \alpha ) } = \frac{ \frac{4}{5} }{ \frac{3}{5} } \\ = \frac{4}{5} \times \frac{5}{3} = \frac{4}{3} \\ please \: note \: here \: we \: have \: used \: alpha \: \: \: in \: place \: of \: theta$

Answer 2

sec theta = 5/3

sin theta = 4/5

Tan theta = 4/3