if cos theta=√3/5 then find sin theta and tan theta ?
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Answer:
Step-by-step explanation:
cos theta=/3/5=base/hypotenuse
by Pythagoras theorem
(hypotenuse)^2=(base)^2+(perpendicular)^2
(5)^2-(/3)^2=(perpendicular)^2
/22=perpendicular
sin theta=perpendicular/hypotenuse=/22/5
tan theta=perpendicular/base=/22//3
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