Question

if cos theta =3/5 then find the value of 5 sin theta - 6 tan^2 theta​

Answer 1

Step-by-step explanation:

cos o = base/hypotenuse =3/5

opposite side =sqrt(5²-3²) = 4

sin o= oppositeside/hypotenuse=4/5

tan o=sin o/ cos o=4/3

tan² o = 4²/3² = 16/9

5sin o -6tan²o

=5×4/5 - 6×(16/9) = 4- 32/3 = -6.67