If cos theta =3/5 then sin theta sec theta tan theta is equal to
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1/secthita=costhita so
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ab^2 + bc^2 = ac^2
ab^2 = 25-9 = 16
ab = 4
let theta be A
sinA = 4/5
secA = 5/3
tanA =4/5 x 5/3
= 4/5 x 5/3 x4/3
= 16 / 9
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