Question

if cos theta =3/5 then what is the value of 6 tan theta minus 5 cos theta​

Answer 1

Answer:

cos theta 3\5

tan theta4\3

therefore

6*4\3-5*3\5

8-3

5

Answer 2

$Cos \theta = \frac{3}{5} \: --(1)$

$i) Sin^{2} \theta = 1 - cos^{2} \theta \\= 1 - \Big(\frac{3}{5}\Big)^{2} \\= 1 - \frac{9}{25} \\= \frac{25-9}{25} \\= \frac{16}{25}$

$sin \theta = \sqrt{ \frac{16}{25} } \\= \frac{4}{5} \: --(2)$

$ii) tan \theta = \frac{sin \theta }{cos \theta } \\= \frac{\frac{4}{5}}{\frac{3}{5}}\\= \frac{4}{3} \: --(3)$

$Now, \red{ Value \:of \: 6 tan \theta - 5 cos \theta } \\= 6 \times \frac{4}{3} - 5 \times \frac{3}{5} \\= 2 \times 4 - 3 \\= 8 - 3 \\= 5$

Therefore.,

$\red{ Value \:of \: 6 tan \theta - 5 cos \theta } \\\green { = 5}$

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