if cos theta =35/37find sin and tan theta no cheat plz important hai
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Answered by
1
cos theta = 35/37 = BASE/HYPOTENUSE
Therefore, let base be 35k and Hypotenuse be 37k
P^2 + B^2 = H^2
P^2 = H^2-B^2
= 37^2 - 35^2
= 1369-1225
= 144k^2
P = root144k^2
P= 12k
We know,
Sin theta = P/H = 12k/37k = 12/37
Tan theta = P/B = 12k/35k = 12/35
Thus, sin theta = 12/37 and tan theta = 12/35
Hope this helps! :)
Therefore, let base be 35k and Hypotenuse be 37k
P^2 + B^2 = H^2
P^2 = H^2-B^2
= 37^2 - 35^2
= 1369-1225
= 144k^2
P = root144k^2
P= 12k
We know,
Sin theta = P/H = 12k/37k = 12/37
Tan theta = P/B = 12k/35k = 12/35
Thus, sin theta = 12/37 and tan theta = 12/35
Hope this helps! :)
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5
Answer:
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